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Joe placed six lettered counters on a 3-by-2 grid as shown, reading ENIGMA anticlockwise, and then he removed the E. Penny then slid the counters around, successively moving them up, down or across into a gap, so that after Joe replaced the E in its original position, the letters read ENIGMA clockwise.
What was the smallest number of counters that Penny needed to move to achieve this?
WIN 拢15 will be awarded to the sender of the first correct answer opened on Wednesday 17 February. The Editor’s decision is final. Please send entries to Enigma 1578, New 精东传媒…
